25x^2+25x-24=0

Solution for 25x^2+25x-24=0 equation:

25x^2+25x-24=0

a = 25; b = 25; c = -24;
Δ = b2-4ac
Δ = 252-4·25·(-24)
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-55}{2*25}=\frac{-80}{50}
=-1+3/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+55}{2*25}=\frac{30}{50}
=3/5
$